Question

Two rhombuses have sides with lengths of `15`. If one rhombus has a corner with an angle of `(3pi)/8` and the other has a corner with an angle of `(11pi)/12`, what is the difference between the areas of the rhombuses?

Answer 1

Difference between areas of the two rhombuses is 44.3763

Explanation:

Area of rhombus `= (1/2) * d_1 * d_2 or a * h`
Where `d_1 , d_2` are the diagonals, a is the side and h is the altitude.

In this case we will use the formula Area = a * h.

Rhombus 1
`h = a sin theta = 15 * sin ((3pi)/8) = 13.8582`
Area = a * h = 15 * 13.8582 = 207.873#

Rhombus 2
`h = a sin theta = 15 * sin ((11pi)/12) = 3.8823`
Area = a * h = 15 * 3.8823 = 58.2345#

Hence the difference in areas is `58.2345 - 13.8582 = 44.3763`