How do you graph #y>log_10(x+1)#?

1 Answer
Rhys
Dec 9, 2017

As shown in the graph

Explanation:

The first we consider is the graph of #log_10 (x+1) # this is just #log_10(x) # undergoing the transformation of being shifted 1 to the left:

#Log_10(x)# :
graph{log(x) [-1.25, 8.75, -2.64, 2.36]}

#log_10(x+1) #: graph{log(x+1) [-2.168, 7.83, -2.62, 2.38]}

Now we must consider the inequality: Where the values of y are greater than #log_10(x+1)#, we see this must be above the function, where below the function the value of #y# is smaller than the fucntion

#=># graph{y>log(x+1) [-2.105, 7.893, -2.3, 2.7]}

Now we see that it cuts of at #x=-1# this is due to the fucntion being underfined for #x<=-1#

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