How do you find the intercepts, asymptotes and graph f(x)= 4^(x+1)-5?

1 Answer
Dec 10, 2017

See the following :)

Explanation:

When x=0, y=f(0)=4^(0+1)-5=4^1-5=4-5=-1
So, the y-intercept is (0,-1).

When y=0, which means f(x)=0
4^(x+1)-5=0
4^(x+1)=5

take log on both sides:
log4^(x+1)=log5
(x+1)log4=log5
xlog4+log4=log5
x=(log5-log4)/log4=0.160964047
Therefore, x-intercept is (0.16, 0).

graph{4^(x+1)-5 [-18.48, 18.47, -9.24, 9.24]}