Question

What is the slope of the tangent line of `r=sin(theta/4)/sin(theta/2)` at `theta=(-3pi)/2`?

Answer 1

-0.48

Explanation:

Slope of a polar curve r= `f(theta)` is

The given curve is

=`sin (theta/4) /(2sin(theta/4)cos(theta/4))= sec(theta/4)`

`(dr)/(d theta)= 1/4 sec(theta/4)tan(theta/4)`

Slope would thus be

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