Question

An object with a mass of `5 kg` is on a surface with a kinetic friction coefficient of `4`. How much force is necessary to accelerate the object horizontally at `1 m/s^2`?

Answer 1

The force is `=201N`

Explanation:

The mass of the object is `m=5kg`

The acceleration is `a=8ms^-2`

The coefficient of kinetic friction is

`mu_k=F_r/N=4`

The normal force is `N=5gN`

The frictional force is `F_r=mu_k xx N=4*5g=20gN`

The force necessary to accelerate the object is `=FN`

The acceleration due to gravity is `g=9.8ms^-2`

The acceleration of the object is `a=1ms^-1`

According to Newton's Second Law

`F-F_r=ma`

`F=ma+F_r=((5xx1)+(20g))N=201N`