How do you graph #y= |x - 2| + 2#?

1 Answer
Dec 26, 2017

you can see that:
when #x=2#, #y(2)=abs(2-2)+2=0+2=2#

when #x=1#, #y(1)=abs(1-2)+2=1+2=3#
when #x=3#, #y(3)=abs(3-2)+2=1+2=3#

when #x=0#, #y(0)=abs(0-2)+2=2+2=4#
when #x=4#, #y(4)=abs(4-2)+2=2+2=4#

when #x=-1#, #y(-1)=abs(-1-2)+2=3+2=5#
when #x=5#, #y(5)=abs(5-2)+2=3+2=5#

and so on, in general:
when #x=2-a#, #y(2-a)=abs(cancel(2)-acancel(-2))+2=abs(-a)+2=a+2#
when #x=2+a#, #y(2+a)=abs(cancel(2)+acancel(-2))+2=abs(+a)+2=a+2#

We see this is a linear

so the graph will have a min when #x=2# and go linear in each side (down when #x<2# and up when #x>2#)

graph{abs(x-2)+2 [-10, 10, -1, 9]}