How do you graph #x=(y+4)^2-2#?

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Answer 1 · 2017-12-28T09:06:06

See below

#x=(y+4)^2-2#

We need to isolate #y#

#(y+4)^2 =x+2#

#y+4 = +-sqrt(x+2)#

#y = +-sqrt(x+2)-4#

We can now graph #y# as below:

graph{((sqrt(x+2)-4)-y)((-sqrt(x+2)-4)-y)=0 [-12.4, 28.13, -11.59, 8.69]}