How do you find the intercepts, vertex and graph #f(x)=x^2+4#?
1 Answer
Vertex:
x-intercept: doesn't exist
y-intercept:
Explanation:
The x-vertex of a quadratic equation
In the equation
Therefore, the x-vertex is
Plugging in
Therefore, the y-vertex is
Combine the x-vertex and the y-vertex to get the vertex coordinates.
Vertex:
The x-intercept is given by plugging in
Therefore, there is no x-intercept.
The y-intercept is given by plugging in
Therefore, the y-intercept is at
Here is the graph for
graph{x^2+4 [-20.17, 19.83, -1.2, 18.8]}
I hope that helps!