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Answer 1 · 2018-01-05T16:06:18

We know that #1" amu"=1.6606xx10^-27" kg"#
Velocity of light #c# in vacuum is #=2.9979xx10^8" ms"^-1#

Using the Einstein's mass equivalence relation we get energy equivalent of

#1" amu"=931.5" MeV"#

Now mass of #1# proton#=1.007276471" amu"#
#:.# mass of #2# proton#=1.007276471xx2" amu"#

Energy equivalent of #2# protons #=1.007276471xx2xx931.5xx10^6#

#=1.88xx10^9" eV"#

We know that #1" eV"=1.60218xx10^-19" J"#
#:.# Energy equivalent of #2# protons #=1.88xx10^9xx1.60218xx10^-19#

#=3.0xx10^-10" J"#