Question

How do you differentiate the following parametric equation: `x(t)=e^t/(t+t)^2-1, y(t)=t-e^(t)`?

Answer 1

`dx/dt= (e^t 4t^2 -8te^t)/(16t^4)`

`dy/dt= 1-e^t`

Explanation:

Both the equations would need to be differentiated seperatly as follows:

`x(t)= e^t /(4t^2)-1`

Therefore `dx/dt= (e^t 4t^2 -8te^t)/(16t^4)`

`y(t)=t-e^t`

therefore `dy/dt= 1-e^t`