Question

Two opposite sides of a parallelogram have lengths of `7`. If one corner of the parallelogram has an angle of `pi/4` and the parallelogram's area is `42`, how long are the other two sides?

Answer 1

Other two sides are `8.49` unit long.

Explanation:

We know the area of the parallelogram is

`A_p=s_1*s_2*sin theta`

Where `s_1=7,s_2=?,theta=pi/4=180/4=45^0` are the adjacent

sides and corner angle respectively.

`A_p=42 :. 42=7*s_2*sin45 or s_2= 42/(7*sin45)` or

`s_2 ~~8.49` unit. Other two sides are `8.49` unit long. [Ans]