What is the amplitude of #y=1/2costheta#?

Question

1556 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-21T03:57:12

The 'peak to peak' amptitude of #y# is #1#

#y=1/2cos theta#

Remember, #-1<=cos theta<=1 forall theta in RR#

Hence, #-1/2<=1/2cos theta<=1/2#

The 'peak to peak' amptitude of a periodic funtion measures the distance between the maximum and minimum values over a single period.

Hence, the 'peak to peak' amptitude of #y# is #1/2 -(-1/2) =1#

We can see this from the graph of #y# below.

graph{1/2cosx [-0.425, 6.5, -2.076, 1.386]}