The rate of the following reaction is 0.960 M/s. What is the relative rate of change of each species in the reaction? A + 3B -> 2CA+3B2C

1 Answer
Jan 26, 2018

A + 3B -> 2CA+3B2C

It’s given that

"0.960 M/s" = -(d[A])/dt = -1/3(d[B])/dt = 1/2(d[C])/dt0.960 M/s=d[A]dt=13d[B]dt=12d[C]dt

So,

(d[A])/dt = -"0.960 M/s"d[A]dt=0.960 M/s

(d[B])/dt = -3 × "0.960 M/s" = -"2.88 M/s"d[B]dt=3×0.960 M/s=2.88 M/s

(d[C])/dt = 2 × "0.960 M/s" = "1.92 M/s"d[C]dt=2×0.960 M/s=1.92 M/s