Question

A triangle has sides A, B, and C. Sides A and B are of lengths `2` and `12`, respectively, and the angle between A and B is `(7pi)/12`. What is the length of side C?

Answer 1

`c approx 12.666`

Explanation:

Given `a=2`, `b=12`, and `C=(7pi)/12`, we can calculate side `c` using the Law of Cosines:

`c=sqrt(a^2+b^2-2abcos(C))`

`c=sqrt(2^2+12^2-2(2)(12)cos((7pi)/12))`

`c approx 12.666`