Question

Question #583b0

Answer 1

1.429 g/L

Explanation:

We know that one mole of any substance at STP will occupy a volume of `22.4` liters. We know that oxygen is diatomic, therefore one mole of oxygen weights `"32 g"`.

Apply the density formula:

`rho =m/V`

`rho =("32 g O"_2) /("22.4 L")`

You get

`rho = "1.42857 g/L"`

you round it up to `"1.429 g/L"`.