Question #83103

1 Answer
Feb 16, 2018

#y=(5/2)x+0#

Explanation:

First step is to find the y intercept, where #x=0#
#x=(2/5)y#
#(0)=(2/5)y#
#(0)/(2/5)=((2/5)y)/(2/5)#
#y=0#

This means that when #x=0#, then #y=0#, which can be described as #(0,0)#, and means that this line passes through the origin.

Now we can convert to the slope-intercept form, #y=mx+b#
#x=(2/5)y#
#x/(2/5)=((2/5)y)/(2/5)#
#x(5/2)=y#
#y=(5/2)x+0#

Breaking down this equation will help you graph it. b is the y intercept, or where the line crosses the y axis. Since the origin is a defined point, that is the y intercept

m represents the slope, which shows the direction and angle of the line. This is also described as 'rise over run.' Since the slope is #5/2#, then from the y intercept (the origin), count up 5 and to the right 2. this is represented as #(2,5)#. From here, you can continue plotting points by adding 5 to each y value as you add 2 to each x value.

graph{y=5/2(x) [-10, 10, -5, 5]}