Question

If a spring has a constant of `4 (kg)/s^2`, how much work will it take to extend the spring by `78 cm`?

Answer 1

Work done in extending a spring ,is stored in it as elastic potential energy,and that is expressed as `1/2 kx^2`(where, `k` is the spring constant and `x` is the amount by which it is extended)

Given, `k=4 , x=78/100`

So, work done = `1/2 *4 (78/100)^2=1.217 J`