How do you find the amplitude, period and phase shift for #y=cos(theta+180^circ)#?

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Answer 1 · 2018-03-01T11:08:34

#color(blue)(Amplitude = 1, Period = 2pi, Phase# shift # color(blue)(-pi)# #color(white)(aa) color(red)((pi^c)# to the left

Using the standard form of equation #y = a cos(btheta - c) + d#,

find amplitude and phase shift of the given equation.

Given #y = cos (theta + 180)#

#a = 1,b = 1, c = -180, d = 0#

Amplitude # = a = 1#

Period # = (2pi) /| b| = 2pi#

Phase shift # c / b = -180#. #(pi^c# to the left)

graph{cos(x + pi) [-10, 10, -5, 5]} + pi) [-10, 10, -5, 5]}