How do you write an equation of a line with Slope = -5, passing through (-4, -2)?

1 Answer
Mar 2, 2018

#y=-5x-22#

Explanation:

The point-slope form of a line is given by the formula

#y-y_1=m(x-x_1)#

Where #(x_1,y_1)# is a point through which the line passes and #m# is the line's slope. We have all information required to use this formula, so let's simply plug in #(x_1,y_1)=(-4,-2), m=-5# into the above formula:

#y-(-2)=-5(x-(-4))#

Simplify.

#y+2=-5(x+4)#

(Subtracting a negative is the same as adding)

#y+2=-5x+4(-5)#

Distributive Property.

#y+2=-5x-20#

Solve for #y:#

#ycancel(+2-2)=-5x-20-2#

#y=-5x-22#