How do you find the product #(x-6)^2#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Shiva Prakash M V Mar 2, 2018 #(x-6)^2=x^2-12x+36# Explanation: To find #(x-6)^2# #(x-6)^2=(x-6)(x-6)# #(x-6)(x-6)=x*x-6*x-x*6+6xx6# #=x^2-6x-6x+36# #=x^2-12x+36# Thus, #(x-6)^2=x^2-12x+36# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 10734 views around the world You can reuse this answer Creative Commons License