How do you find the amplitude, period, and shift for #y= 4/3 cos (x/2)#?

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Answer 1 · 2018-03-04T02:10:49

#Amplitude = a = (4/3)#

#Period #= (2pi) / |b| = 4pi#

Phase shift #= c / b = 0 color(white)(aaa)# #color(red)(0 )# to the right#

Standard form of equation for cosine function is

#y = a cos (b x - c) + d#

#y = (4/3) cos (x/2)#

#Amplitude = a = (4/3)#

#Period #= (2pi) / |b| = (2pi) / (1/2) = 4pi#

Phase shift #= c / b = 0 color(white)(aaa)# #color(red)(0 )# to the right#

graph{(4/3) cos (x/2) [-10, 10, -5, 5]}