Question

What is the angular momentum of an object with a mass of `4 kg` that moves along a circular path of radius `2 m` at a frequency of `1 Hz`?

Answer 1

Angular momentum is expressed as `Iomega` (where, `I` is the moment of inertia and `omega` is the angular velocity)

In this case given, `nu=1 Hz`

we know, `omega =2pinu=2pi*1=2pi rads^-1`

And moment of inertia of the object,w.r.t the centre of thr circular pathway it is moving is `Mr^2 =4*(2)^2 =16Kg.m^2`

So,angular momentum of this object is `16*2pi=100.531Kgm^2rads^-1`

Answer 2

The angular momentum is `=100.5kgm^2s^-1`

Explanation:

The angular momentum is `L=Iomega`

where `I` is the moment of inertia

The mass of the object is `m=4kg`

The radius of the path is `r=2m`

The moment of inertia of the object is given by

`I=mr^2`

`=4*2^2= 16 kgm^2`

The frequency is `f=1Hz`

The angular velocity is `omega=2pif=2*1*pi=2pirads^-1`

The angular momentum is

`L=Iomega=16*2pi=100.5kgm^2s^-1`