How do you simplify $(6i)(-8i)$ ?

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Answer 1 · 2018-03-04T11:28:17

48

Considering $i$ as the imaginary number, defined as $i^2=-1$

$(6i)*(-8i)=(-8*6)i^2=-48i^2=48$

Answer 2 · 2018-03-04T11:28:56

It becomes 48.

If you multiply them together, you get $-48i^2$ . Since $i$ is $sqrt(-1)$ , then $i^2= -1$ . $-48*-1=48$ . Hope this helped.

How do you simplify (6i)(-8i)(6i)(-8i)?