How do you use the quadratic formula to solve #x^2+6x+10=0#?

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Answer 1 · 2018-03-04T12:43:25

Solution: #x= -3+1i and x= -3-1i #

# x^2+6x+10=0 #

Comparing with standard quadratic equation #ax^2+bx+c=0#

# a=1 ,b=6 ,c=10# Discriminant # D= b^2-4ac# or

#D=36-40 =-4# If discriminant positive, we get two real

solutions, if it is zero we get just one solution, and if it is negative

we get complex solutions. Discriminant is negative , so it has

complex roots. .Quadratic formula: #x= (-b+-sqrtD)/(2a) #or

#x= (-6+-sqrt(-4))/(-2) = -3+- i [i^2=-1]#

So roots are #x= -3+1i and x= -3-1i # [Ans]