How do you use the quadratic formula to solve $x^{2} + 6 x + 10 = 0$ $x^2+6x+10=0$ ?

Question

14258 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-04T12:43:25

Solution: $x = - 3 + 1 i and x = - 3 - 1 i$ $x= -3+1i and x= -3-1i$

$x^{2} + 6 x + 10 = 0$ $x^2+6x+10=0$

Comparing with standard quadratic equation $a x^{2} + b x + c = 0$ $ax^2+bx+c=0$

$a = 1, b = 6, c = 10$ $a=1 ,b=6 ,c=10$ Discriminant $D = b^{2} - 4 a c$ $D= b^2-4ac$ or

$D = 36 - 40 = - 4$ $D=36-40 =-4$ If discriminant positive, we get two real

solutions, if it is zero we get just one solution, and if it is negative

we get complex solutions. Discriminant is negative , so it has

complex roots. .Quadratic formula: $x = \frac{- b \pm \sqrt{D}}{2 a}$ $x= (-b+-sqrtD)/(2a)$ or

$x = \frac{- 6 \pm \sqrt{- 4}}{- 2} = - 3 \pm i [i^{2} = - 1]$ $x= (-6+-sqrt(-4))/(-2) = -3+- i [i^2=-1]$

So roots are $x = - 3 + 1 i and x = - 3 - 1 i$ $x= -3+1i and x= -3-1i$ [Ans]

How do you use the quadratic formula to solve x^2+6x+10=0x2+6x+10=0x^2+6x+10=0?