How do you factor completely $6 x^{2} - 13 x + 6$ $6x^2-13x+6$ ?

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Answer 1 · 2018-03-04T13:02:32

given,

$6 x^{2} - 13 x + 6$ $6x^2 -13x+6$

$= 6 x^{2} - 9 x - 4 x + 6$ $=6x^2 -9x -4x +6$

$= 3 x (2 x - 3) - 2 (3 x - 3)$ $=3x(2x-3) -2(3x-3)$

$= (2 x - 3) (3 x - 2)$ $=(2x-3) (3x-2)$

How do you factor completely 6x^2-13x+66x2−13x+66x^2-13x+6?