How do you simplify #(4x + 5)^2#?

Question

5176 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-04T15:54:22

#=16x^2+40x+25#

#(4x+5)^2#

#=(4x+5)(4x+5)#

Distribute

#=(4x)(4x)+(4x)(5)+(5)(4x)+(5)(5)#

#=16x^2+20x+20x+25#

#=16x^2+40x+25#

Answer 2 · 2018-03-04T15:59:03

#16x^2+40x+25#

This is a perfect square:

#(a+b)^2=a^2+2ab+b^2#

Plug in:

#16x^2+2*4x*5+25#

#16x^2+40x+25#

You could also write it out:

#(4x+5)(4x+5)#

#16x^2+20x+20x+25#

#16x^2+40x+25#