How do you find the value of ${tan}^{- 1} (\frac{2}{3})$ $tan^-1 (2/3)$ ?

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Answer 1 · 2018-03-04T16:18:31

$33^{\circ} 69 + k 180^{\circ}$ $33^@69 + k180^@$

Call x the arc whose tan is 2/3.
$tan x = \frac{2}{3}$ $tan x = 2/3$
Use calculator -->
$x = 33^{\circ} 69 + k 180^{\circ}$ $x = 33^@69 + k180^@$

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