How do you solve #x/2 + 3 = 3#?

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Answer 1 · 2018-03-04T18:14:04

#color(magenta)(x=0#

#x/2+3=3#

#x/2=3-3#

#x/2=0#

#x=0xx2#

#color(magenta)(x=0#

~Hope this helps! :)

Answer 2 · 2018-03-04T18:17:09

See a solution process below:

First, subtract #color(red)(3)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#x/2 + 3 - color(red)(3) = 3 - color(red)(3)#

#x/2 + 0 = 0#

#x/2 = 0#

Now, multiply each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#color(red)(2) xx x/2 = color(red)(2) xx 0#

#cancel(color(red)(2)) xx x/color(red)(cancel(color(black)(2))) = 0#

#x = 0#