How do you solve $\frac{x}{2} + 3 = 3$ $x/2 + 3 = 3$ ?

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Answer 1 · 2018-03-04T18:14:04

$x = 0$ $color(magenta)(x=0$

$\frac{x}{2} + 3 = 3$ $x/2+3=3$

$\frac{x}{2} = 3 - 3$ $x/2=3-3$

$\frac{x}{2} = 0$ $x/2=0$

$x = 0 \times 2$ $x=0xx2$

$x = 0$ $color(magenta)(x=0$

~Hope this helps! :)

Answer 2 · 2018-03-04T18:17:09

See a solution process below:

First, subtract $3$ $color(red)(3)$ from each side of the equation to isolate the $x$ $x$ term while keeping the equation balanced:

$\frac{x}{2} + 3 - 3 = 3 - 3$ $x/2 + 3 - color(red)(3) = 3 - color(red)(3)$

$\frac{x}{2} + 0 = 0$ $x/2 + 0 = 0$

$\frac{x}{2} = 0$ $x/2 = 0$

Now, multiply each side of the equation by $2$ $color(red)(2)$ to solve for $x$ $x$ while keeping the equation balanced:

$2 \times \frac{x}{2} = 2 \times 0$ $color(red)(2) xx x/2 = color(red)(2) xx 0$

$cancel(color(red)(2)) xx x/color(red)(cancel(color(black)(2))) = 0$

$x = 0$

How do you solve x/2 + 3 = 3x2+3=3x/2 + 3 = 3?