Question

A circuit with a resistance of `3 Omega` has a fuse with a capacity of `2 A`. Can a voltage of `2 V` be applied to the circuit without blowing the fuse?

Answer 1

yes

Explanation:

`V = IR`

voltage = current * resistance

here, `R = 3Omega`

and `V = 2V`

`I = V/R = (2V)/(3Omega)`

`I = 2/3A`

when a voltage of `2V` is applied, the current is `2/3A`.

a fuse blows when the current goes beyond a certain level.

if the capacity of the fuse is `2A`, the fuse will blow at any current higher than `2A`.

`2/3 A < 2A`

there is not enough current for the fuse to blow.

a voltage of `2V` can be applied without blowing the fuse.