How do you write a linear equation that goes through (1,-6) and is parallel to the line x + 2y = 6?

1 Answer
Mar 5, 2018

x + 2y + 11 = 0

is the required equation of the line.

Explanation:

x+2y=6" " " "(1)

The slope of the line = -1/2

The slope of a line parallel to line (1) will be same

"slope" = m = -1/2

Now, the equation of the line through (1,-6) with a slope m =-1/2 by using the point-slope form is

y-y_1= m (x-x_1)

y - (-6) = -1/2(x-1)

y + 6 = -1/2(x-1)

2y + 12 = -x + 1

or

x + 2y + 11 = 0