How do you write a linear equation that goes through (1,-6) and is parallel to the line #x + 2y = 6#?

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Answer 1 · 2018-03-05T16:42:38

# x + 2y + 11 = 0#

is the required equation of the line.

#x+2y=6" " " "(1)#

The slope of the line #= -1/2#

The slope of a line parallel to line (1) will be same

#"slope" = m = -1/2#

Now, the equation of the line through #(1,-6)# with a slope #m =-1/2# by using the point-slope form is

#y-y_1= m (x-x_1)#

#y - (-6) = -1/2(x-1)#

#y + 6 = -1/2(x-1)#

#2y + 12 = -x + 1#

or

# x + 2y + 11 = 0 #