What is the solution to the system $x+y=2$ and $x-y=6$ ?

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Answer 1 · 2018-03-06T03:17:02

$x = 4" and " y = -2$

Add the two equations eliminating $y$ to solve for $x$

$" "x + y = 2$
$+x -y = 6$
$2x + 0y = 8$

$2x = 8" "$ divide each side by 2

$(2x)/2 = 8/2$

$x = 4 " "$ Substitute 4 for x and solve for y

$4 + y = 2 " "$ subtract 4 from each side

$4 -4 + y = 2 -4" "$ This gives

$y = -2$

What is the solution to the system x+y=2x+y=2 and x-y=6x-y=6?