Question

How do you find the product of `(6x + 7)^2`?

Answer 1

See a solution process below:

Explanation:

This is a special form of the quadratic:

`(color(red)(a) + color(blue)(b))^2 = (color(red)(a) + color(blue)(b))(color(red)(a) + color(blue)(b)) = color(red)(a)^2 + 2color(red)(a)color(blue)(b) + color(blue)(b)^2`

Let:

`a = 6x` and `b = 7`

Substituting gives:

`(color(red)(6x) + color(blue)(7))^2 =>`

`(color(red)(6x) + color(blue)(7))(color(red)(6x) + color(blue)(7)) =>`

`color(red)((6x))^2 + (2 xx color(red)(6x) xx color(blue)(7)) + color(blue)(7)^2 =>`

`36x^2 + 84x + 49`