How do you factor #b^2 + 12b + 32#?
1 Answer
Mar 7, 2018
Explanation:
#"the factors of + 32 which sum to + 12 are + 4 and + 8"#
#rArrb^2+12b+32=(b+4)(b+8)#
#"the factors of + 32 which sum to + 12 are + 4 and + 8"#
#rArrb^2+12b+32=(b+4)(b+8)#