Question

How do you factor `b^3 - 8`?

Answer 1

`(b-2)(b^2+2b+4)`

Explanation:

`b^3-8`
`rArr (b)^3-(2)^3`
`rArr (b-2)^3+3*b*2(b-2)`
`rArr (b-2)[(b-2)^2+6b]`
`rArr (b-2)[b^2-4b+4+6b]`
`rArr (b-2)(b^2+2b+4)`