How do you factor b^3 - 8? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Nityananda · Nam D. Mar 7, 2018 (b-2)(b^2+2b+4) Explanation: b^3-8 rArr (b)^3-(2)^3 rArr (b-2)^3+3*b*2(b-2) rArr (b-2)[(b-2)^2+6b] rArr (b-2)[b^2-4b+4+6b] rArr (b-2)(b^2+2b+4) Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor x^3 -8? What are the factors of x^3y^6 – 64? How do you know if x^2 + 10x + 25 is a perfect square? How do you write 16x^2 – 48x + 36 as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor 16x^2-36 using the difference of squares? How do you factor 2x^4y^2-32? How do you factor x^2 - 27? See all questions in Factor Polynomials Using Special Products Impact of this question 2687 views around the world You can reuse this answer Creative Commons License