How do you solve #root 3(3x-1)=2#?

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Answer 1 · 2018-03-09T06:28:27

The solution is #x=3#.

Cube both sides of the equals sign, then solve for #x#:

# root(3)(3x-1)=2 #

# (root(color(red)cancelcolor(black)3)(3x-1))^color(red)cancelcolor(black)3=2^3 #

# 3x-1=2^3 #

# 3x-1=8 #

# 3x=9 #

# x=3 #

Answer 2 · 2018-03-09T06:31:00

#x=3#

#root(3)(3x-1)=2#
#(3x-1)=2^3#
#(3x-1)=8#
#3x=9#
#x=3#