What is the electric current produced when a voltage of #15 V# is applied to a circuit with a resistance of #6 Omega#?

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Answer 1 · 2018-03-10T19:32:55

#2.5 amperes#

The formula needed to solve this question is defined by Ohms Law

#V=IR#

Which we can rearrange to find the current

#I=V/R#

Where

#I# = Current (#amperes#)
#R# = Resistance (#ohms#)
#V# = Potential Difference (#vol#t#s#)

Substitute in the values you already have into the formula

#I#=#15/6#

#:.# #I = 2.5 amperes#

Answer 2 · 2018-03-11T01:08:53

#2.5 \ "A"#

We use Ohm's law here, which states that

#V=IR#

where #V# is the voltage, #I# is the current in amperes, and #R# is the resistance in ohms.

We need to solve for current, so we can rearrange the equation into

#I=V/R#

Plugging in the given values, we get

#I=(15 \ "V")/(6 \ Omega)#

#=2.5 \ "A"#

So, the electric current has a strength of #2.5# amperes.