How do you factor #k^2 + k - 110#?

Question

1310 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-11T14:04:00

#color(blue)((k-10)(k+11)#

Given:

Factorize: #color(red)(k^2 + k - 110#

#y=f(x) = k^2 + k - 110#

Split the middle term to factorize.

#k^2 -10k+11k - 110#

Break the expression into appropriate groups.

Factor #k# and #11# respectively as shown below:

#k(k-10)+11(k-10)#

Next, factor the common term: #(k-10)#

#color(blue)((k-10)(k+11)#

Hope you find this solution useful.