How do you find the period and amplitude of #y=5/2cos(x/4)#?
1 Answer
Mar 12, 2018
Explanation:
#"the standard form of the cosine function is"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#
#"where amplitude "=|a|," period "=(2pi)/b#
#"phase shift "=-c/b" and vertical shift "=d#
#"here "a=5/2,b=1/4,c=d=0#
#"amplitude "=|5/2|=5/2," period "=(2pi)/(1/4)=8pi#