How do you find the period and amplitude of #y=5/2cos(x/4)#?

1 Answer
Mar 12, 2018

#"period "=8pi" and amplitude "=5/2#

Explanation:

#"the standard form of the cosine function is"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period "=(2pi)/b#

#"phase shift "=-c/b" and vertical shift "=d#

#"here "a=5/2,b=1/4,c=d=0#

#"amplitude "=|5/2|=5/2," period "=(2pi)/(1/4)=8pi#