How do you factor $3 x^{3} - 9 x^{2}$ $3x^3 - 9x^2$ ?

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Answer 1 · 2018-03-12T19:01:06

$3 x^{2} (x - 3)$ $3x^2(x-3)$

$3 x^{3} - 9 x^{2} = x \cdot 3 x^{2} - 3 \cdot 3 x^{2} = 3 x^{2} (x - 3)$ $3x^3 - 9x^2=x*3x^2-3*3x^2=3x^2(x-3)$

Answer 2 · 2018-03-12T19:02:22

$3 x^{3} - 9 x^{2}$ $3x^3-9x^2$
$3 x^{2} (x - 3)$ $3x^2(x-3)$

This equation Has roots x=0 and x=3
As ,at these two points the above equation is $= 0$ $=0$

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