Question

How do you solve for y in `3x - 2y = 10`?

Answer 1

See a solution process below:

Explanation:

First, subtract `color(red)(3x)` from each side of the equation to isolate the `y` term while keeping the equation balanced:

`3x - 2y = 10`

`-color(red)(3x) + 3x - 2y = -color(red)(3x) + 10`

`0 - 2y = -3x + 10`

`-2y = -3x + 10`

Now, divide each side of the equation by `color(red)(-2)` to solve for `y` while keeping the equation balanced:

`(-2y)/color(red)(-2) = (-3x + 10)/color(red)(-2)`

`(color(red)(cancel(color(black)(-2)))y)/cancel(color(red)(-2)) = (-3x)/color(red)(-2) + 10/color(red)(-2)`

`y = (-3)/color(red)(-2)x + (-5)`

`y = 3/2x - 5`