How do you find the perimeter of a triangle whose coordinates are X(0,2), Y(4,-1), Z(-2,-1)?

1 Answer
Mar 13, 2018

11 +sqrt13

Explanation:

You can use Pythagorus' Theorem (a^2 + b^2 = c^2)to find the lengths of the sides.

Therefore the length of side XY is sqrt((4-0)^2 + ((-1)-2)^2) = sqrt(4^2 + (-3)^2) = sqrt(16 + 9) = sqrt25 = 5

Side YZ: sqrt(((-2)-4)^2 + ((-1)-(-1))^2) = sqrt((-6)^2 + 0^2) = sqrt(36) = 6

Side XZ: sqrt(((-2)-0)^2 + ((-1)-2)^2) = sqrt((-2)^2 + (-3)^2) = sqrt(4 + 9) = sqrt13

Perimeter = XY + YZ + XZ = 5 + 6 + sqrt13 = 11 +sqrt13