Question

How do you use implicit differentiation to find dy/dx given `x^2-2y^2+x+3y-4=0`?

Answer 1

`dy/dx = (2x+1)/(2y-3)`

Explanation:

Differentiate both sides of the equation with respect to `x`:

`d/dx (x^2-2y^2+x+3y-4) = 0`

`2x -2ydy/dx+1 +3dy/dx = 0`

`2x +1 = (2y-3) dy/dx`

`dy/dx = (2x+1)/(2y-3)`