Question

How much work would it take to push a `9 kg` weight up a `5 m` plane that is at an incline of `pi / 4`?

Answer 1

`311,8J`

Explanation:

Work must be done against the component of the weight force parallel to the incline as this the direction in which the object moves. Assuming the actual path length is the 5 m slope, we get :

`therefore W=vecF . vecx`

`=mgxsintheta`

`=9xx9,8xx5xxsin(pi/4)`

`=311,8J`