How do you evaluate #5/6-2/3#?
3 Answers
Explanation:
Both fractions must have the same denominators before you can add the numerators:.
Explanation:
#"before subtracting the fractions we require them to have"#
#"a "color(blue)"common denominator"#
#"this is achieved by multiplying numerator/denominator"#
#"of "2/3" by 2, thus making the denominator 6"#
#rArr5/6-((2xxcolor(red)(2))/(3xxcolor(red)(2)))#
#=5/6-4/6#
#"now subtract the numerators leaving the denominator"#
#=(5-4)/6=1/6#
Make both numbers have a common denominator of 6, then just subtract to get
Explanation:
To subtract the numerators (numbers at the top), find a common denominator (number at the bottom), which in this case I'll use 6, since 6 is a common multiple of both 6 and 3
So to convert
So you replace
To get the answer