How do you multiply #(c^4+c^2)(c^4-c^2)#?

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Answer 1 · 2018-03-16T22:24:25

#(c^4+c^2)(c^4-c^2)=color(blue)(c^8-c^4#

Multiply (Expand):

#(c^4+c^2)(c^4-c^2)#

Use the difference of squares:

#a^2-b^2=(a+b)(a-b),#

where:

#a=c^4# and #b=c^2#.

#(c^4)^2-(c^2)^2#

Apply power rule: #(a^m)^n=a^(m*n)#

#c^(4*2)-c^(2*2)#

Simplify.

#c^8-c^4#