How do you find the amplitude, period, and shift for y= -3 sin 2 pi x?

1 Answer
Mar 19, 2018

As below.

Explanation:

y = A sin (Bx - C) + D

Given : y = -3 sin (2 pi x)

Amplitude = |A| = 3

"Period" = P = (2pi) / |B| = cancel(2pi) / cancel(2pi) = 1

"Phase Shift " = (-C) / B = 0 / (2pi) = 0

"Vertical Shift" = D = 0

graph{-3 sin (2 pi x) [-10, 10, -5, 5]}