Question

What is the pOH of a `4.8xx10^(-10) M` `H^+` solution?

Answer 1

`pOH-=4.68`

Explanation:

For aqueous solutions we know that `pH+pOH=14`...

And so `pOH=14-pH`...

And since ...........

`pH=-log_10[H^+]=-log_10(4.8xx10^-10)=-(-9.32)=+9.32....`

`pOH=14-9.32=4.68`...