Question

If an object is moving at `10 m/s` over a surface with a kinetic friction coefficient of `u_k=2 /g`, how far will the object continue to move?

Answer 1

`"25 m"`

Explanation:

Acceleration of object `= -μ_k"g" = -2/cancel("g") × cancel("g") = -"2 m/s"^2`

`"S" = -("u"^2)/(2a) color(white)(....)[∵ "v" = 0]`

`"S" = -(("10 m/s")^2)/(2 × (-"2 m/s"^2)) = "25 m"`