How do you solve #4x(x+2)=16x-3# by factoring?

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Answer 1 · 2018-03-20T06:57:07

#color(green)(x = 3/2, 1/2#

#4x (x + 2) = 16x - 3#

#4x^2 + 8x = 16x - 3, "Removing bracket in L H S"#

#4x^2 + 8x - 16x + 3 = 0, "bringing all terms to L H S"#

#4x^2 - 8x + 3 = 0#

$4x^2 - 2x - 6x + 3 = 0#

#2x (2x - 1) - 3 (2x - 1) = 0#

(2x -3) * (2x - 1) = 0#

#color(green)(x = 3/2, 1/2#